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authorVincent Palatin <vpalatin@chromium.org>2011-03-02 17:25:02 -0500
committerBlue Swirl <blauwirbel@gmail.com>2011-03-05 12:00:59 +0000
commit60c07d933c66c4b30a83b7ccbc8a0cb3df1b2d0e (patch)
treea60247ab922b1d6a4af7aeb1e636bbc880a9f67c /cursor_hidden.xpm
parent24ac3a7d4eacea38d514dbf50baa845e5bc6840b (diff)
downloadhqemu-60c07d933c66c4b30a83b7ccbc8a0cb3df1b2d0e.zip
hqemu-60c07d933c66c4b30a83b7ccbc8a0cb3df1b2d0e.tar.gz
net: fix qemu_can_send_packet logic
If any of the clients is not ready to receive (ie it has a can_receive callback and can_receive() returns false), we don't want to start sending, else this client may miss/discard the packet. I got this behaviour with the following setup : the emulated machine is using an USB-ethernet adapter, it is connected to the network using SLIRP and I'm dumping the traffic in a .pcap file. As per the following command line : -net nic,model=usb,vlan=1 -net user,vlan=1 -net dump,vlan=1,file=/tmp/pkt.pcap Every time that two packets are coming in a row from the host, the usb-net code will receive the first one, then returns 0 to can_receive call since it has a 1 packet long queue. But as the dump code is always ready to receive, qemu_can_send_packet will return true and the next packet will discard the previous one in the usb-net code. Signed-off-by: Vincent Palatin <vpalatin@chromium.org> Signed-off-by: Blue Swirl <blauwirbel@gmail.com>
Diffstat (limited to 'cursor_hidden.xpm')
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