scale = 20
for (i=0; i<10000; i++) {
for (j=1; j<100; j++) b=i*j
}
b
for (i=0; i<10000; i++) {
for (j=1000000000000000000000000000000000000000000000000000000000000000000; \
j<1000000000000000000000000000000000000000000000000000000000000000100; \
j++) b=i*j
}
b
quit