[IA64] Fix unaligned handler for floating point instructions with base update

The compiler team did the hard work for this distilling a problem in
large fortran application which showed up when applied to a 290MB input
data set down to this instruction:

	ldfd f34=[r17],-8

Which they noticed incremented r17 by 0x10 rather than decrementing it
by 8 when the value in r17 caused an unaligned data fault.  I tracked
it down to some bad instruction decoding in unaligned.c. The code
assumes that the 'x' bit can determine whether the instruction is
an "ldf" or "ldfp" ... which it is for opcode=6 (see table 4-29 on
page 3:302 of the SDM).  But for opcode=7 the 'x' bit is irrelevent,
all variants are "ldf" instructions (see table 4-36 on page 3:306).

Note also that interpreting the instruction as "ldfp" means that the
"paired" floating point register (f35 in the example here) will also
be corrupted.

Signed-off-by: Tony Luck <tony.luck@intel.com>

1 files changed, 7 insertions, 4 deletions

diff --git a/arch/ia64/kernel/unaligned.c b/arch/ia64/kernel/unaligned.c
index 2173de9..f6a1aeb 100644
--- a/arch/ia64/kernel/unaligned.c
+++ b/arch/ia64/kernel/unaligned.c
@@ -1488,16 +1488,19 @@ ia64_handle_unaligned (unsigned long ifa, struct pt_regs *regs)
 	      case LDFA_OP:
 	      case LDFCCLR_OP:
 	      case LDFCNC_OP:
-	      case LDF_IMM_OP:
-	      case LDFA_IMM_OP:
-	      case LDFCCLR_IMM_OP:
-	      case LDFCNC_IMM_OP:
 		if (u.insn.x)
 			ret = emulate_load_floatpair(ifa, u.insn, regs);
 		else
 			ret = emulate_load_float(ifa, u.insn, regs);
 		break;
 
+	      case LDF_IMM_OP:
+	      case LDFA_IMM_OP:
+	      case LDFCCLR_IMM_OP:
+	      case LDFCNC_IMM_OP:
+		ret = emulate_load_float(ifa, u.insn, regs);
+		break;
+
 	      case STF_OP:
 	      case STF_IMM_OP:
 		ret = emulate_store_float(ifa, u.insn, regs);