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path: root/crypto/openssl/crypto/bn/bn_recp.c
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Diffstat (limited to 'crypto/openssl/crypto/bn/bn_recp.c')
-rw-r--r--crypto/openssl/crypto/bn/bn_recp.c48
1 files changed, 29 insertions, 19 deletions
diff --git a/crypto/openssl/crypto/bn/bn_recp.c b/crypto/openssl/crypto/bn/bn_recp.c
index d019941..ef5fdd4 100644
--- a/crypto/openssl/crypto/bn/bn_recp.c
+++ b/crypto/openssl/crypto/bn/bn_recp.c
@@ -93,18 +93,19 @@ void BN_RECP_CTX_free(BN_RECP_CTX *recp)
int BN_RECP_CTX_set(BN_RECP_CTX *recp, const BIGNUM *d, BN_CTX *ctx)
{
- BN_copy(&(recp->N),d);
- BN_zero(&(recp->Nr));
+ if (!BN_copy(&(recp->N),d)) return 0;
+ if (!BN_zero(&(recp->Nr))) return 0;
recp->num_bits=BN_num_bits(d);
recp->shift=0;
return(1);
}
-int BN_mod_mul_reciprocal(BIGNUM *r, BIGNUM *x, BIGNUM *y, BN_RECP_CTX *recp,
- BN_CTX *ctx)
+int BN_mod_mul_reciprocal(BIGNUM *r, const BIGNUM *x, const BIGNUM *y,
+ BN_RECP_CTX *recp, BN_CTX *ctx)
{
int ret=0;
BIGNUM *a;
+ const BIGNUM *ca;
BN_CTX_start(ctx);
if ((a = BN_CTX_get(ctx)) == NULL) goto err;
@@ -114,19 +115,19 @@ int BN_mod_mul_reciprocal(BIGNUM *r, BIGNUM *x, BIGNUM *y, BN_RECP_CTX *recp,
{ if (!BN_sqr(a,x,ctx)) goto err; }
else
{ if (!BN_mul(a,x,y,ctx)) goto err; }
+ ca = a;
}
else
- a=x; /* Just do the mod */
+ ca=x; /* Just do the mod */
- BN_div_recp(NULL,r,a,recp,ctx);
- ret=1;
+ ret = BN_div_recp(NULL,r,ca,recp,ctx);
err:
BN_CTX_end(ctx);
return(ret);
}
-int BN_div_recp(BIGNUM *dv, BIGNUM *rem, BIGNUM *m, BN_RECP_CTX *recp,
- BN_CTX *ctx)
+int BN_div_recp(BIGNUM *dv, BIGNUM *rem, const BIGNUM *m,
+ BN_RECP_CTX *recp, BN_CTX *ctx)
{
int i,j,ret=0;
BIGNUM *a,*b,*d,*r;
@@ -146,8 +147,8 @@ int BN_div_recp(BIGNUM *dv, BIGNUM *rem, BIGNUM *m, BN_RECP_CTX *recp,
if (BN_ucmp(m,&(recp->N)) < 0)
{
- BN_zero(d);
- BN_copy(r,m);
+ if (!BN_zero(d)) return 0;
+ if (!BN_copy(r,m)) return 0;
BN_CTX_end(ctx);
return(1);
}
@@ -157,20 +158,28 @@ int BN_div_recp(BIGNUM *dv, BIGNUM *rem, BIGNUM *m, BN_RECP_CTX *recp,
* we need multiply ABCDEF by 3 digests of the reciprocal of ab
*
*/
- i=BN_num_bits(m);
+ /* i := max(BN_num_bits(m), 2*BN_num_bits(N)) */
+ i=BN_num_bits(m);
j=recp->num_bits<<1;
if (j>i) i=j;
- j>>=1;
+ /* Nr := round(2^i / N) */
if (i != recp->shift)
recp->shift=BN_reciprocal(&(recp->Nr),&(recp->N),
- i,ctx);
+ i,ctx); /* BN_reciprocal returns i, or -1 for an error */
+ if (recp->shift == -1) goto err;
- if (!BN_rshift(a,m,j)) goto err;
+ /* d := |round(round(m / 2^BN_num_bits(N)) * recp->Nr / 2^(i - BN_num_bits(N)))|
+ * = |round(round(m / 2^BN_num_bits(N)) * round(2^i / N) / 2^(i - BN_num_bits(N)))|
+ * <= |(m / 2^BN_num_bits(N)) * (2^i / N) * (2^BN_num_bits(N) / 2^i)|
+ * = |m/N|
+ */
+ if (!BN_rshift(a,m,recp->num_bits)) goto err;
if (!BN_mul(b,a,&(recp->Nr),ctx)) goto err;
- if (!BN_rshift(d,b,i-j)) goto err;
+ if (!BN_rshift(d,b,i-recp->num_bits)) goto err;
d->neg=0;
+
if (!BN_mul(b,&(recp->N),d,ctx)) goto err;
if (!BN_usub(r,m,b)) goto err;
r->neg=0;
@@ -201,20 +210,21 @@ err:
* We actually calculate with an extra word of precision, so
* we can do faster division if the remainder is not required.
*/
-int BN_reciprocal(BIGNUM *r, BIGNUM *m, int len, BN_CTX *ctx)
+/* r := 2^len / m */
+int BN_reciprocal(BIGNUM *r, const BIGNUM *m, int len, BN_CTX *ctx)
{
int ret= -1;
BIGNUM t;
BN_init(&t);
- BN_zero(&t);
+ if (!BN_zero(&t)) goto err;
if (!BN_set_bit(&t,len)) goto err;
if (!BN_div(r,NULL,&t,m,ctx)) goto err;
+
ret=len;
err:
BN_free(&t);
return(ret);
}
-
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