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-rw-r--r--sys/i386/isa/clock.c33
-rw-r--r--sys/isa/atrtc.c33
2 files changed, 44 insertions, 22 deletions
diff --git a/sys/i386/isa/clock.c b/sys/i386/isa/clock.c
index d474259..1c82ffa 100644
--- a/sys/i386/isa/clock.c
+++ b/sys/i386/isa/clock.c
@@ -401,10 +401,7 @@ getit(void)
{
int high, low;
-#ifdef KDB
- if (!kdb_active)
-#endif
- mtx_lock_spin(&clock_lock);
+ mtx_lock_spin(&clock_lock);
/* Select timer0 and latch counter value. */
outb(TIMER_MODE, TIMER_SEL0 | TIMER_LATCH);
@@ -412,11 +409,7 @@ getit(void)
low = inb(TIMER_CNTR0);
high = inb(TIMER_CNTR0);
-#ifdef KDB
- if (!kdb_active)
-#endif
- mtx_unlock_spin(&clock_lock);
-
+ mtx_unlock_spin(&clock_lock);
return ((high << 8) | low);
}
@@ -457,8 +450,18 @@ DELAY(int n)
* takes about 1.5 usec for each of the i/o's in getit(). The loop
* takes about 6 usec on a 486/33 and 13 usec on a 386/20. The
* multiplications and divisions to scale the count take a while).
+ *
+ * However, if ddb is active then use a fake counter since reading
+ * the i8254 counter involves acquiring a lock. ddb must not do
+ * locking for many reasons, but it calls here for at least atkbd
+ * input.
*/
- prev_tick = getit();
+#ifdef KDB
+ if (kdb_active)
+ prev_tick = 1;
+ else
+#endif
+ prev_tick = getit();
n -= 0; /* XXX actually guess no initial overhead */
/*
* Calculate (n * (timer_freq / 1e6)) without using floating point
@@ -485,7 +488,15 @@ DELAY(int n)
/ 1000000;
while (ticks_left > 0) {
- tick = getit();
+#ifdef KDB
+ if (kdb_active) {
+ inb(0x84);
+ tick = prev_tick - 1;
+ if (tick <= 0)
+ tick = timer0_max_count;
+ } else
+#endif
+ tick = getit();
#ifdef DELAYDEBUG
++getit_calls;
#endif
diff --git a/sys/isa/atrtc.c b/sys/isa/atrtc.c
index d474259..1c82ffa 100644
--- a/sys/isa/atrtc.c
+++ b/sys/isa/atrtc.c
@@ -401,10 +401,7 @@ getit(void)
{
int high, low;
-#ifdef KDB
- if (!kdb_active)
-#endif
- mtx_lock_spin(&clock_lock);
+ mtx_lock_spin(&clock_lock);
/* Select timer0 and latch counter value. */
outb(TIMER_MODE, TIMER_SEL0 | TIMER_LATCH);
@@ -412,11 +409,7 @@ getit(void)
low = inb(TIMER_CNTR0);
high = inb(TIMER_CNTR0);
-#ifdef KDB
- if (!kdb_active)
-#endif
- mtx_unlock_spin(&clock_lock);
-
+ mtx_unlock_spin(&clock_lock);
return ((high << 8) | low);
}
@@ -457,8 +450,18 @@ DELAY(int n)
* takes about 1.5 usec for each of the i/o's in getit(). The loop
* takes about 6 usec on a 486/33 and 13 usec on a 386/20. The
* multiplications and divisions to scale the count take a while).
+ *
+ * However, if ddb is active then use a fake counter since reading
+ * the i8254 counter involves acquiring a lock. ddb must not do
+ * locking for many reasons, but it calls here for at least atkbd
+ * input.
*/
- prev_tick = getit();
+#ifdef KDB
+ if (kdb_active)
+ prev_tick = 1;
+ else
+#endif
+ prev_tick = getit();
n -= 0; /* XXX actually guess no initial overhead */
/*
* Calculate (n * (timer_freq / 1e6)) without using floating point
@@ -485,7 +488,15 @@ DELAY(int n)
/ 1000000;
while (ticks_left > 0) {
- tick = getit();
+#ifdef KDB
+ if (kdb_active) {
+ inb(0x84);
+ tick = prev_tick - 1;
+ if (tick <= 0)
+ tick = timer0_max_count;
+ } else
+#endif
+ tick = getit();
#ifdef DELAYDEBUG
++getit_calls;
#endif
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