For the P function, the newline must be considered a part of the pattern

space, so when printing it, don't let the pattern space and the output run
into eachother by omitting the \n when printing.

2 files changed, 12 insertions, 1 deletions

diff --git a/tools/regression/usr.bin/sed/regress.P.out b/tools/regression/usr.bin/sed/regress.P.out
new file mode 100644
index 0000000..4d3284f
--- /dev/null
+++ b/tools/regression/usr.bin/sed/regress.P.out
@@ -0,0 +1,8 @@
+input
+input
+data
+data
+for validation
+for validation
+of sed(1)
+of sed(1)
diff --git a/tools/regression/usr.bin/sed/regress.sh b/tools/regression/usr.bin/sed/regress.sh
index 10cc001..9198b3f 100644
--- a/tools/regression/usr.bin/sed/regress.sh
+++ b/tools/regression/usr.bin/sed/regress.sh
@@ -9,12 +9,15 @@ cd $TESTDIR
 
 STATUS=0
 
-for test in G psl; do
+for test in G P psl; do
   echo "Running test $test"
   case "$test" in
   G)
     sed G < regress.in | diff -u regress.$test.out -
     ;;
+  P)
+    sed P < regress.in | diff -u regress.$test.out -
+    ;;
   psl)	
     sed '$!g; P; D' < regress.in | diff -u regress.$test.out -
     ;;