Properly initialize the last active time of the initial thread. This fixes

the case that a CPU hungry main thread is prevented from being preempted
due to a negative calculation of its time slice.

Reported by:	Alexander Litvin <archer@lucky.net>

1 files changed, 6 insertions, 0 deletions

diff --git a/lib/libpthread/thread/thr_init.c b/lib/libpthread/thread/thr_init.c
index 051483f..b6429bb 100644
--- a/lib/libpthread/thread/thr_init.c
+++ b/lib/libpthread/thread/thr_init.c
@@ -90,6 +90,7 @@ _thread_init(void)
 	int             i;
 	size_t		len;
 	int		mib[2];
+	struct timeval	tv;
 	struct clockinfo clockinfo;
 	struct sigaction act;
 
@@ -223,6 +224,11 @@ _thread_init(void)
 		TAILQ_INIT(&(_thread_initial->mutexq));
 		_thread_initial->priority_mutex_count = 0;
 
+		/* Initialize last active time to now: */
+		gettimeofday(&tv, NULL);
+		_thread_initial->last_active.tv_sec = tv.tv_sec;
+		_thread_initial->last_active.tv_usec = tv.tv_usec;
+
 		/* Initialise the rest of the fields: */
 		_thread_initial->poll_data.nfds = 0;
 		_thread_initial->poll_data.fds = NULL;