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author | markm <markm@FreeBSD.org> | 1998-09-09 07:00:04 +0000 |
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committer | markm <markm@FreeBSD.org> | 1998-09-09 07:00:04 +0000 |
commit | 4fcbc3669aa997848e15198cc9fb856287a6788c (patch) | |
tree | 58b20e81687d6d5931f120b50802ed21225bf440 /contrib/perl5/pod/perlre.pod | |
download | FreeBSD-src-4fcbc3669aa997848e15198cc9fb856287a6788c.zip FreeBSD-src-4fcbc3669aa997848e15198cc9fb856287a6788c.tar.gz |
Initial import of Perl5. The king is dead; long live the king!
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diff --git a/contrib/perl5/pod/perlre.pod b/contrib/perl5/pod/perlre.pod new file mode 100644 index 0000000..382ba65 --- /dev/null +++ b/contrib/perl5/pod/perlre.pod @@ -0,0 +1,929 @@ +=head1 NAME + +perlre - Perl regular expressions + +=head1 DESCRIPTION + +This page describes the syntax of regular expressions in Perl. For a +description of how to I<use> regular expressions in matching +operations, plus various examples of the same, see discussion +of C<m//>, C<s///>, C<qr//> and C<??> in L<perlop/"Regexp Quote-Like Operators">. + +The matching operations can have various modifiers. The modifiers +that relate to the interpretation of the regular expression inside +are listed below. For the modifiers that alter the way a regular expression +is used by Perl, see L<perlop/"Regexp Quote-Like Operators"> and +L<perlop/"Gory details of parsing quoted constructs">. + +=over 4 + +=item i + +Do case-insensitive pattern matching. + +If C<use locale> is in effect, the case map is taken from the current +locale. See L<perllocale>. + +=item m + +Treat string as multiple lines. That is, change "^" and "$" from matching +at only the very start or end of the string to the start or end of any +line anywhere within the string, + +=item s + +Treat string as single line. That is, change "." to match any character +whatsoever, even a newline, which it normally would not match. + +The C</s> and C</m> modifiers both override the C<$*> setting. That is, no matter +what C<$*> contains, C</s> without C</m> will force "^" to match only at the +beginning of the string and "$" to match only at the end (or just before a +newline at the end) of the string. Together, as /ms, they let the "." match +any character whatsoever, while yet allowing "^" and "$" to match, +respectively, just after and just before newlines within the string. + +=item x + +Extend your pattern's legibility by permitting whitespace and comments. + +=back + +These are usually written as "the C</x> modifier", even though the delimiter +in question might not actually be a slash. In fact, any of these +modifiers may also be embedded within the regular expression itself using +the new C<(?...)> construct. See below. + +The C</x> modifier itself needs a little more explanation. It tells +the regular expression parser to ignore whitespace that is neither +backslashed nor within a character class. You can use this to break up +your regular expression into (slightly) more readable parts. The C<#> +character is also treated as a metacharacter introducing a comment, +just as in ordinary Perl code. This also means that if you want real +whitespace or C<#> characters in the pattern (outside of a character +class, where they are unaffected by C</x>), that you'll either have to +escape them or encode them using octal or hex escapes. Taken together, +these features go a long way towards making Perl's regular expressions +more readable. Note that you have to be careful not to include the +pattern delimiter in the comment--perl has no way of knowing you did +not intend to close the pattern early. See the C-comment deletion code +in L<perlop>. + +=head2 Regular Expressions + +The patterns used in pattern matching are regular expressions such as +those supplied in the Version 8 regex routines. (In fact, the +routines are derived (distantly) from Henry Spencer's freely +redistributable reimplementation of the V8 routines.) +See L<Version 8 Regular Expressions> for details. + +In particular the following metacharacters have their standard I<egrep>-ish +meanings: + + \ Quote the next metacharacter + ^ Match the beginning of the line + . Match any character (except newline) + $ Match the end of the line (or before newline at the end) + | Alternation + () Grouping + [] Character class + +By default, the "^" character is guaranteed to match at only the +beginning of the string, the "$" character at only the end (or before the +newline at the end) and Perl does certain optimizations with the +assumption that the string contains only one line. Embedded newlines +will not be matched by "^" or "$". You may, however, wish to treat a +string as a multi-line buffer, such that the "^" will match after any +newline within the string, and "$" will match before any newline. At the +cost of a little more overhead, you can do this by using the /m modifier +on the pattern match operator. (Older programs did this by setting C<$*>, +but this practice is now deprecated.) + +To facilitate multi-line substitutions, the "." character never matches a +newline unless you use the C</s> modifier, which in effect tells Perl to pretend +the string is a single line--even if it isn't. The C</s> modifier also +overrides the setting of C<$*>, in case you have some (badly behaved) older +code that sets it in another module. + +The following standard quantifiers are recognized: + + * Match 0 or more times + + Match 1 or more times + ? Match 1 or 0 times + {n} Match exactly n times + {n,} Match at least n times + {n,m} Match at least n but not more than m times + +(If a curly bracket occurs in any other context, it is treated +as a regular character.) The "*" modifier is equivalent to C<{0,}>, the "+" +modifier to C<{1,}>, and the "?" modifier to C<{0,1}>. n and m are limited +to integral values less than 65536. + +By default, a quantified subpattern is "greedy", that is, it will match as +many times as possible (given a particular starting location) while still +allowing the rest of the pattern to match. If you want it to match the +minimum number of times possible, follow the quantifier with a "?". Note +that the meanings don't change, just the "greediness": + + *? Match 0 or more times + +? Match 1 or more times + ?? Match 0 or 1 time + {n}? Match exactly n times + {n,}? Match at least n times + {n,m}? Match at least n but not more than m times + +Because patterns are processed as double quoted strings, the following +also work: + + \t tab (HT, TAB) + \n newline (LF, NL) + \r return (CR) + \f form feed (FF) + \a alarm (bell) (BEL) + \e escape (think troff) (ESC) + \033 octal char (think of a PDP-11) + \x1B hex char + \c[ control char + \l lowercase next char (think vi) + \u uppercase next char (think vi) + \L lowercase till \E (think vi) + \U uppercase till \E (think vi) + \E end case modification (think vi) + \Q quote (disable) pattern metacharacters till \E + +If C<use locale> is in effect, the case map used by C<\l>, C<\L>, C<\u> +and C<\U> is taken from the current locale. See L<perllocale>. + +You cannot include a literal C<$> or C<@> within a C<\Q> sequence. +An unescaped C<$> or C<@> interpolates the corresponding variable, +while escaping will cause the literal string C<\$> to be matched. +You'll need to write something like C<m/\Quser\E\@\Qhost/>. + +In addition, Perl defines the following: + + \w Match a "word" character (alphanumeric plus "_") + \W Match a non-word character + \s Match a whitespace character + \S Match a non-whitespace character + \d Match a digit character + \D Match a non-digit character + +A C<\w> matches a single alphanumeric character, not a whole +word. To match a word you'd need to say C<\w+>. If C<use locale> is in +effect, the list of alphabetic characters generated by C<\w> is taken +from the current locale. See L<perllocale>. You may use C<\w>, C<\W>, +C<\s>, C<\S>, C<\d>, and C<\D> within character classes (though not as +either end of a range). + +Perl defines the following zero-width assertions: + + \b Match a word boundary + \B Match a non-(word boundary) + \A Match only at beginning of string + \Z Match only at end of string, or before newline at the end + \z Match only at end of string + \G Match only where previous m//g left off (works only with /g) + +A word boundary (C<\b>) is defined as a spot between two characters that +has a C<\w> on one side of it and a C<\W> on the other side of it (in +either order), counting the imaginary characters off the beginning and +end of the string as matching a C<\W>. (Within character classes C<\b> +represents backspace rather than a word boundary.) The C<\A> and C<\Z> are +just like "^" and "$", except that they won't match multiple times when the +C</m> modifier is used, while "^" and "$" will match at every internal line +boundary. To match the actual end of the string, not ignoring newline, +you can use C<\z>. The C<\G> assertion can be used to chain global +matches (using C<m//g>), as described in +L<perlop/"Regexp Quote-Like Operators">. + +It is also useful when writing C<lex>-like scanners, when you have several +patterns that you want to match against consequent substrings of your +string, see the previous reference. +The actual location where C<\G> will match can also be influenced +by using C<pos()> as an lvalue. See L<perlfunc/pos>. + +When the bracketing construct C<( ... )> is used, \E<lt>digitE<gt> matches the +digit'th substring. Outside of the pattern, always use "$" instead of "\" +in front of the digit. (While the \E<lt>digitE<gt> notation can on rare occasion work +outside the current pattern, this should not be relied upon. See the +WARNING below.) The scope of $E<lt>digitE<gt> (and C<$`>, C<$&>, and C<$'>) +extends to the end of the enclosing BLOCK or eval string, or to the next +successful pattern match, whichever comes first. If you want to use +parentheses to delimit a subpattern (e.g., a set of alternatives) without +saving it as a subpattern, follow the ( with a ?:. + +You may have as many parentheses as you wish. If you have more +than 9 substrings, the variables $10, $11, ... refer to the +corresponding substring. Within the pattern, \10, \11, etc. refer back +to substrings if there have been at least that many left parentheses before +the backreference. Otherwise (for backward compatibility) \10 is the +same as \010, a backspace, and \11 the same as \011, a tab. And so +on. (\1 through \9 are always backreferences.) + +C<$+> returns whatever the last bracket match matched. C<$&> returns the +entire matched string. (C<$0> used to return the same thing, but not any +more.) C<$`> returns everything before the matched string. C<$'> returns +everything after the matched string. Examples: + + s/^([^ ]*) *([^ ]*)/$2 $1/; # swap first two words + + if (/Time: (..):(..):(..)/) { + $hours = $1; + $minutes = $2; + $seconds = $3; + } + +Once perl sees that you need one of C<$&>, C<$`> or C<$'> anywhere in +the program, it has to provide them on each and every pattern match. +This can slow your program down. The same mechanism that handles +these provides for the use of $1, $2, etc., so you pay the same price +for each pattern that contains capturing parentheses. But if you never +use $&, etc., in your script, then patterns I<without> capturing +parentheses won't be penalized. So avoid $&, $', and $` if you can, +but if you can't (and some algorithms really appreciate them), once +you've used them once, use them at will, because you've already paid +the price. As of 5.005, $& is not so costly as the other two. + +Backslashed metacharacters in Perl are +alphanumeric, such as C<\b>, C<\w>, C<\n>. Unlike some other regular +expression languages, there are no backslashed symbols that aren't +alphanumeric. So anything that looks like \\, \(, \), \E<lt>, \E<gt>, +\{, or \} is always interpreted as a literal character, not a +metacharacter. This was once used in a common idiom to disable or +quote the special meanings of regular expression metacharacters in a +string that you want to use for a pattern. Simply quote all +non-alphanumeric characters: + + $pattern =~ s/(\W)/\\$1/g; + +Now it is much more common to see either the quotemeta() function or +the C<\Q> escape sequence used to disable all metacharacters' special +meanings like this: + + /$unquoted\Q$quoted\E$unquoted/ + +Perl defines a consistent extension syntax for regular expressions. +The syntax is a pair of parentheses with a question mark as the first +thing within the parentheses (this was a syntax error in older +versions of Perl). The character after the question mark gives the +function of the extension. Several extensions are already supported: + +=over 10 + +=item C<(?#text)> + +A comment. The text is ignored. If the C</x> switch is used to enable +whitespace formatting, a simple C<#> will suffice. Note that perl closes +the comment as soon as it sees a C<)>, so there is no way to put a literal +C<)> in the comment. + +=item C<(?:pattern)> + +=item C<(?imsx-imsx:pattern)> + +This is for clustering, not capturing; it groups subexpressions like +"()", but doesn't make backreferences as "()" does. So + + @fields = split(/\b(?:a|b|c)\b/) + +is like + + @fields = split(/\b(a|b|c)\b/) + +but doesn't spit out extra fields. + +The letters between C<?> and C<:> act as flags modifiers, see +L<C<(?imsx-imsx)>>. In particular, + + /(?s-i:more.*than).*million/i + +is equivalent to more verbose + + /(?:(?s-i)more.*than).*million/i + +=item C<(?=pattern)> + +A zero-width positive lookahead assertion. For example, C</\w+(?=\t)/> +matches a word followed by a tab, without including the tab in C<$&>. + +=item C<(?!pattern)> + +A zero-width negative lookahead assertion. For example C</foo(?!bar)/> +matches any occurrence of "foo" that isn't followed by "bar". Note +however that lookahead and lookbehind are NOT the same thing. You cannot +use this for lookbehind. + +If you are looking for a "bar" that isn't preceded by a "foo", C</(?!foo)bar/> +will not do what you want. That's because the C<(?!foo)> is just saying that +the next thing cannot be "foo"--and it's not, it's a "bar", so "foobar" will +match. You would have to do something like C</(?!foo)...bar/> for that. We +say "like" because there's the case of your "bar" not having three characters +before it. You could cover that this way: C</(?:(?!foo)...|^.{0,2})bar/>. +Sometimes it's still easier just to say: + + if (/bar/ && $` !~ /foo$/) + +For lookbehind see below. + +=item C<(?E<lt>=pattern)> + +A zero-width positive lookbehind assertion. For example, C</(?E<lt>=\t)\w+/> +matches a word following a tab, without including the tab in C<$&>. +Works only for fixed-width lookbehind. + +=item C<(?<!pattern)> + +A zero-width negative lookbehind assertion. For example C</(?<!bar)foo/> +matches any occurrence of "foo" that isn't following "bar". +Works only for fixed-width lookbehind. + +=item C<(?{ code })> + +Experimental "evaluate any Perl code" zero-width assertion. Always +succeeds. C<code> is not interpolated. Currently the rules to +determine where the C<code> ends are somewhat convoluted. + +The C<code> is properly scoped in the following sense: if the assertion +is backtracked (compare L<"Backtracking">), all the changes introduced after +C<local>isation are undone, so + + $_ = 'a' x 8; + m< + (?{ $cnt = 0 }) # Initialize $cnt. + ( + a + (?{ + local $cnt = $cnt + 1; # Update $cnt, backtracking-safe. + }) + )* + aaaa + (?{ $res = $cnt }) # On success copy to non-localized + # location. + >x; + +will set C<$res = 4>. Note that after the match $cnt returns to the globally +introduced value 0, since the scopes which restrict C<local> statements +are unwound. + +This assertion may be used as L<C<(?(condition)yes-pattern|no-pattern)>> +switch. If I<not> used in this way, the result of evaluation of C<code> +is put into variable $^R. This happens immediately, so $^R can be used from +other C<(?{ code })> assertions inside the same regular expression. + +The above assignment to $^R is properly localized, thus the old value of $^R +is restored if the assertion is backtracked (compare L<"Backtracking">). + +Due to security concerns, this construction is not allowed if the regular +expression involves run-time interpolation of variables, unless +C<use re 'eval'> pragma is used (see L<re>), or the variables contain +results of qr() operator (see L<perlop/"qr/STRING/imosx">). + +This restriction is due to the wide-spread (questionable) practice of +using the construct + + $re = <>; + chomp $re; + $string =~ /$re/; + +without tainting. While this code is frowned upon from security point +of view, when C<(?{})> was introduced, it was considered bad to add +I<new> security holes to existing scripts. + +B<NOTE:> Use of the above insecure snippet without also enabling taint mode +is to be severely frowned upon. C<use re 'eval'> does not disable tainting +checks, thus to allow $re in the above snippet to contain C<(?{})> +I<with tainting enabled>, one needs both C<use re 'eval'> and untaint +the $re. + +=item C<(?E<gt>pattern)> + +An "independent" subexpression. Matches the substring that a +I<standalone> C<pattern> would match if anchored at the given position, +B<and only this substring>. + +Say, C<^(?E<gt>a*)ab> will never match, since C<(?E<gt>a*)> (anchored +at the beginning of string, as above) will match I<all> characters +C<a> at the beginning of string, leaving no C<a> for C<ab> to match. +In contrast, C<a*ab> will match the same as C<a+b>, since the match of +the subgroup C<a*> is influenced by the following group C<ab> (see +L<"Backtracking">). In particular, C<a*> inside C<a*ab> will match +fewer characters than a standalone C<a*>, since this makes the tail match. + +An effect similar to C<(?E<gt>pattern)> may be achieved by + + (?=(pattern))\1 + +since the lookahead is in I<"logical"> context, thus matches the same +substring as a standalone C<a+>. The following C<\1> eats the matched +string, thus making a zero-length assertion into an analogue of +C<(?E<gt>...)>. (The difference between these two constructs is that the +second one uses a catching group, thus shifting ordinals of +backreferences in the rest of a regular expression.) + +This construct is useful for optimizations of "eternal" +matches, because it will not backtrack (see L<"Backtracking">). + + m{ \( + ( + [^()]+ + | + \( [^()]* \) + )+ + \) + }x + +That will efficiently match a nonempty group with matching +two-or-less-level-deep parentheses. However, if there is no such group, +it will take virtually forever on a long string. That's because there are +so many different ways to split a long string into several substrings. +This is what C<(.+)+> is doing, and C<(.+)+> is similar to a subpattern +of the above pattern. Consider that the above pattern detects no-match +on C<((()aaaaaaaaaaaaaaaaaa> in several seconds, but that each extra +letter doubles this time. This exponential performance will make it +appear that your program has hung. + +However, a tiny modification of this pattern + + m{ \( + ( + (?> [^()]+ ) + | + \( [^()]* \) + )+ + \) + }x + +which uses C<(?E<gt>...)> matches exactly when the one above does (verifying +this yourself would be a productive exercise), but finishes in a fourth +the time when used on a similar string with 1000000 C<a>s. Be aware, +however, that this pattern currently triggers a warning message under +B<-w> saying it C<"matches the null string many times">): + +On simple groups, such as the pattern C<(?> [^()]+ )>, a comparable +effect may be achieved by negative lookahead, as in C<[^()]+ (?! [^()] )>. +This was only 4 times slower on a string with 1000000 C<a>s. + +=item C<(?(condition)yes-pattern|no-pattern)> + +=item C<(?(condition)yes-pattern)> + +Conditional expression. C<(condition)> should be either an integer in +parentheses (which is valid if the corresponding pair of parentheses +matched), or lookahead/lookbehind/evaluate zero-width assertion. + +Say, + + m{ ( \( )? + [^()]+ + (?(1) \) ) + }x + +matches a chunk of non-parentheses, possibly included in parentheses +themselves. + +=item C<(?imsx-imsx)> + +One or more embedded pattern-match modifiers. This is particularly +useful for patterns that are specified in a table somewhere, some of +which want to be case sensitive, and some of which don't. The case +insensitive ones need to include merely C<(?i)> at the front of the +pattern. For example: + + $pattern = "foobar"; + if ( /$pattern/i ) { } + + # more flexible: + + $pattern = "(?i)foobar"; + if ( /$pattern/ ) { } + +Letters after C<-> switch modifiers off. + +These modifiers are localized inside an enclosing group (if any). Say, + + ( (?i) blah ) \s+ \1 + +(assuming C<x> modifier, and no C<i> modifier outside of this group) +will match a repeated (I<including the case>!) word C<blah> in any +case. + +=back + +A question mark was chosen for this and for the new minimal-matching +construct because 1) question mark is pretty rare in older regular +expressions, and 2) whenever you see one, you should stop and "question" +exactly what is going on. That's psychology... + +=head2 Backtracking + +A fundamental feature of regular expression matching involves the +notion called I<backtracking>, which is currently used (when needed) +by all regular expression quantifiers, namely C<*>, C<*?>, C<+>, +C<+?>, C<{n,m}>, and C<{n,m}?>. + +For a regular expression to match, the I<entire> regular expression must +match, not just part of it. So if the beginning of a pattern containing a +quantifier succeeds in a way that causes later parts in the pattern to +fail, the matching engine backs up and recalculates the beginning +part--that's why it's called backtracking. + +Here is an example of backtracking: Let's say you want to find the +word following "foo" in the string "Food is on the foo table.": + + $_ = "Food is on the foo table."; + if ( /\b(foo)\s+(\w+)/i ) { + print "$2 follows $1.\n"; + } + +When the match runs, the first part of the regular expression (C<\b(foo)>) +finds a possible match right at the beginning of the string, and loads up +$1 with "Foo". However, as soon as the matching engine sees that there's +no whitespace following the "Foo" that it had saved in $1, it realizes its +mistake and starts over again one character after where it had the +tentative match. This time it goes all the way until the next occurrence +of "foo". The complete regular expression matches this time, and you get +the expected output of "table follows foo." + +Sometimes minimal matching can help a lot. Imagine you'd like to match +everything between "foo" and "bar". Initially, you write something +like this: + + $_ = "The food is under the bar in the barn."; + if ( /foo(.*)bar/ ) { + print "got <$1>\n"; + } + +Which perhaps unexpectedly yields: + + got <d is under the bar in the > + +That's because C<.*> was greedy, so you get everything between the +I<first> "foo" and the I<last> "bar". In this case, it's more effective +to use minimal matching to make sure you get the text between a "foo" +and the first "bar" thereafter. + + if ( /foo(.*?)bar/ ) { print "got <$1>\n" } + got <d is under the > + +Here's another example: let's say you'd like to match a number at the end +of a string, and you also want to keep the preceding part the match. +So you write this: + + $_ = "I have 2 numbers: 53147"; + if ( /(.*)(\d*)/ ) { # Wrong! + print "Beginning is <$1>, number is <$2>.\n"; + } + +That won't work at all, because C<.*> was greedy and gobbled up the +whole string. As C<\d*> can match on an empty string the complete +regular expression matched successfully. + + Beginning is <I have 2 numbers: 53147>, number is <>. + +Here are some variants, most of which don't work: + + $_ = "I have 2 numbers: 53147"; + @pats = qw{ + (.*)(\d*) + (.*)(\d+) + (.*?)(\d*) + (.*?)(\d+) + (.*)(\d+)$ + (.*?)(\d+)$ + (.*)\b(\d+)$ + (.*\D)(\d+)$ + }; + + for $pat (@pats) { + printf "%-12s ", $pat; + if ( /$pat/ ) { + print "<$1> <$2>\n"; + } else { + print "FAIL\n"; + } + } + +That will print out: + + (.*)(\d*) <I have 2 numbers: 53147> <> + (.*)(\d+) <I have 2 numbers: 5314> <7> + (.*?)(\d*) <> <> + (.*?)(\d+) <I have > <2> + (.*)(\d+)$ <I have 2 numbers: 5314> <7> + (.*?)(\d+)$ <I have 2 numbers: > <53147> + (.*)\b(\d+)$ <I have 2 numbers: > <53147> + (.*\D)(\d+)$ <I have 2 numbers: > <53147> + +As you see, this can be a bit tricky. It's important to realize that a +regular expression is merely a set of assertions that gives a definition +of success. There may be 0, 1, or several different ways that the +definition might succeed against a particular string. And if there are +multiple ways it might succeed, you need to understand backtracking to +know which variety of success you will achieve. + +When using lookahead assertions and negations, this can all get even +tricker. Imagine you'd like to find a sequence of non-digits not +followed by "123". You might try to write that as + + $_ = "ABC123"; + if ( /^\D*(?!123)/ ) { # Wrong! + print "Yup, no 123 in $_\n"; + } + +But that isn't going to match; at least, not the way you're hoping. It +claims that there is no 123 in the string. Here's a clearer picture of +why it that pattern matches, contrary to popular expectations: + + $x = 'ABC123' ; + $y = 'ABC445' ; + + print "1: got $1\n" if $x =~ /^(ABC)(?!123)/ ; + print "2: got $1\n" if $y =~ /^(ABC)(?!123)/ ; + + print "3: got $1\n" if $x =~ /^(\D*)(?!123)/ ; + print "4: got $1\n" if $y =~ /^(\D*)(?!123)/ ; + +This prints + + 2: got ABC + 3: got AB + 4: got ABC + +You might have expected test 3 to fail because it seems to a more +general purpose version of test 1. The important difference between +them is that test 3 contains a quantifier (C<\D*>) and so can use +backtracking, whereas test 1 will not. What's happening is +that you've asked "Is it true that at the start of $x, following 0 or more +non-digits, you have something that's not 123?" If the pattern matcher had +let C<\D*> expand to "ABC", this would have caused the whole pattern to +fail. +The search engine will initially match C<\D*> with "ABC". Then it will +try to match C<(?!123> with "123", which of course fails. But because +a quantifier (C<\D*>) has been used in the regular expression, the +search engine can backtrack and retry the match differently +in the hope of matching the complete regular expression. + +The pattern really, I<really> wants to succeed, so it uses the +standard pattern back-off-and-retry and lets C<\D*> expand to just "AB" this +time. Now there's indeed something following "AB" that is not +"123". It's in fact "C123", which suffices. + +We can deal with this by using both an assertion and a negation. We'll +say that the first part in $1 must be followed by a digit, and in fact, it +must also be followed by something that's not "123". Remember that the +lookaheads are zero-width expressions--they only look, but don't consume +any of the string in their match. So rewriting this way produces what +you'd expect; that is, case 5 will fail, but case 6 succeeds: + + print "5: got $1\n" if $x =~ /^(\D*)(?=\d)(?!123)/ ; + print "6: got $1\n" if $y =~ /^(\D*)(?=\d)(?!123)/ ; + + 6: got ABC + +In other words, the two zero-width assertions next to each other work as though +they're ANDed together, just as you'd use any builtin assertions: C</^$/> +matches only if you're at the beginning of the line AND the end of the +line simultaneously. The deeper underlying truth is that juxtaposition in +regular expressions always means AND, except when you write an explicit OR +using the vertical bar. C</ab/> means match "a" AND (then) match "b", +although the attempted matches are made at different positions because "a" +is not a zero-width assertion, but a one-width assertion. + +One warning: particularly complicated regular expressions can take +exponential time to solve due to the immense number of possible ways they +can use backtracking to try match. For example this will take a very long +time to run + + /((a{0,5}){0,5}){0,5}/ + +And if you used C<*>'s instead of limiting it to 0 through 5 matches, then +it would take literally forever--or until you ran out of stack space. + +A powerful tool for optimizing such beasts is "independent" groups, +which do not backtrace (see L<C<(?E<gt>pattern)>>). Note also that +zero-length lookahead/lookbehind assertions will not backtrace to make +the tail match, since they are in "logical" context: only the fact +whether they match or not is considered relevant. For an example +where side-effects of a lookahead I<might> have influenced the +following match, see L<C<(?E<gt>pattern)>>. + +=head2 Version 8 Regular Expressions + +In case you're not familiar with the "regular" Version 8 regex +routines, here are the pattern-matching rules not described above. + +Any single character matches itself, unless it is a I<metacharacter> +with a special meaning described here or above. You can cause +characters that normally function as metacharacters to be interpreted +literally by prefixing them with a "\" (e.g., "\." matches a ".", not any +character; "\\" matches a "\"). A series of characters matches that +series of characters in the target string, so the pattern C<blurfl> +would match "blurfl" in the target string. + +You can specify a character class, by enclosing a list of characters +in C<[]>, which will match any one character from the list. If the +first character after the "[" is "^", the class matches any character not +in the list. Within a list, the "-" character is used to specify a +range, so that C<a-z> represents all characters between "a" and "z", +inclusive. If you want "-" itself to be a member of a class, put it +at the start or end of the list, or escape it with a backslash. (The +following all specify the same class of three characters: C<[-az]>, +C<[az-]>, and C<[a\-z]>. All are different from C<[a-z]>, which +specifies a class containing twenty-six characters.) + +Characters may be specified using a metacharacter syntax much like that +used in C: "\n" matches a newline, "\t" a tab, "\r" a carriage return, +"\f" a form feed, etc. More generally, \I<nnn>, where I<nnn> is a string +of octal digits, matches the character whose ASCII value is I<nnn>. +Similarly, \xI<nn>, where I<nn> are hexadecimal digits, matches the +character whose ASCII value is I<nn>. The expression \cI<x> matches the +ASCII character control-I<x>. Finally, the "." metacharacter matches any +character except "\n" (unless you use C</s>). + +You can specify a series of alternatives for a pattern using "|" to +separate them, so that C<fee|fie|foe> will match any of "fee", "fie", +or "foe" in the target string (as would C<f(e|i|o)e>). The +first alternative includes everything from the last pattern delimiter +("(", "[", or the beginning of the pattern) up to the first "|", and +the last alternative contains everything from the last "|" to the next +pattern delimiter. For this reason, it's common practice to include +alternatives in parentheses, to minimize confusion about where they +start and end. + +Alternatives are tried from left to right, so the first +alternative found for which the entire expression matches, is the one that +is chosen. This means that alternatives are not necessarily greedy. For +example: when mathing C<foo|foot> against "barefoot", only the "foo" +part will match, as that is the first alternative tried, and it successfully +matches the target string. (This might not seem important, but it is +important when you are capturing matched text using parentheses.) + +Also remember that "|" is interpreted as a literal within square brackets, +so if you write C<[fee|fie|foe]> you're really only matching C<[feio|]>. + +Within a pattern, you may designate subpatterns for later reference by +enclosing them in parentheses, and you may refer back to the I<n>th +subpattern later in the pattern using the metacharacter \I<n>. +Subpatterns are numbered based on the left to right order of their +opening parenthesis. A backreference matches whatever +actually matched the subpattern in the string being examined, not the +rules for that subpattern. Therefore, C<(0|0x)\d*\s\1\d*> will +match "0x1234 0x4321", but not "0x1234 01234", because subpattern 1 +actually matched "0x", even though the rule C<0|0x> could +potentially match the leading 0 in the second number. + +=head2 WARNING on \1 vs $1 + +Some people get too used to writing things like: + + $pattern =~ s/(\W)/\\\1/g; + +This is grandfathered for the RHS of a substitute to avoid shocking the +B<sed> addicts, but it's a dirty habit to get into. That's because in +PerlThink, the righthand side of a C<s///> is a double-quoted string. C<\1> in +the usual double-quoted string means a control-A. The customary Unix +meaning of C<\1> is kludged in for C<s///>. However, if you get into the habit +of doing that, you get yourself into trouble if you then add an C</e> +modifier. + + s/(\d+)/ \1 + 1 /eg; # causes warning under -w + +Or if you try to do + + s/(\d+)/\1000/; + +You can't disambiguate that by saying C<\{1}000>, whereas you can fix it with +C<${1}000>. Basically, the operation of interpolation should not be confused +with the operation of matching a backreference. Certainly they mean two +different things on the I<left> side of the C<s///>. + +=head2 Repeated patterns matching zero-length substring + +WARNING: Difficult material (and prose) ahead. This section needs a rewrite. + +Regular expressions provide a terse and powerful programming language. As +with most other power tools, power comes together with the ability +to wreak havoc. + +A common abuse of this power stems from the ability to make infinite +loops using regular expressions, with something as innocous as: + + 'foo' =~ m{ ( o? )* }x; + +The C<o?> can match at the beginning of C<'foo'>, and since the position +in the string is not moved by the match, C<o?> would match again and again +due to the C<*> modifier. Another common way to create a similar cycle +is with the looping modifier C<//g>: + + @matches = ( 'foo' =~ m{ o? }xg ); + +or + + print "match: <$&>\n" while 'foo' =~ m{ o? }xg; + +or the loop implied by split(). + +However, long experience has shown that many programming tasks may +be significantly simplified by using repeated subexpressions which +may match zero-length substrings, with a simple example being: + + @chars = split //, $string; # // is not magic in split + ($whitewashed = $string) =~ s/()/ /g; # parens avoid magic s// / + +Thus Perl allows the C</()/> construct, which I<forcefully breaks +the infinite loop>. The rules for this are different for lower-level +loops given by the greedy modifiers C<*+{}>, and for higher-level +ones like the C</g> modifier or split() operator. + +The lower-level loops are I<interrupted> when it is detected that a +repeated expression did match a zero-length substring, thus + + m{ (?: NON_ZERO_LENGTH | ZERO_LENGTH )* }x; + +is made equivalent to + + m{ (?: NON_ZERO_LENGTH )* + | + (?: ZERO_LENGTH )? + }x; + +The higher level-loops preserve an additional state between iterations: +whether the last match was zero-length. To break the loop, the following +match after a zero-length match is prohibited to have a length of zero. +This prohibition interacts with backtracking (see L<"Backtracking">), +and so the I<second best> match is chosen if the I<best> match is of +zero length. + +Say, + + $_ = 'bar'; + s/\w??/<$&>/g; + +results in C<"<><b><><a><><r><>">. At each position of the string the best +match given by non-greedy C<??> is the zero-length match, and the I<second +best> match is what is matched by C<\w>. Thus zero-length matches +alternate with one-character-long matches. + +Similarly, for repeated C<m/()/g> the second-best match is the match at the +position one notch further in the string. + +The additional state of being I<matched with zero-length> is associated to +the matched string, and is reset by each assignment to pos(). + +=head2 Creating custom RE engines + +Overloaded constants (see L<overload>) provide a simple way to extend +the functionality of the RE engine. + +Suppose that we want to enable a new RE escape-sequence C<\Y|> which +matches at boundary between white-space characters and non-whitespace +characters. Note that C<(?=\S)(?<!\S)|(?!\S)(?<=\S)> matches exactly +at these positions, so we want to have each C<\Y|> in the place of the +more complicated version. We can create a module C<customre> to do +this: + + package customre; + use overload; + + sub import { + shift; + die "No argument to customre::import allowed" if @_; + overload::constant 'qr' => \&convert; + } + + sub invalid { die "/$_[0]/: invalid escape '\\$_[1]'"} + + my %rules = ( '\\' => '\\', + 'Y|' => qr/(?=\S)(?<!\S)|(?!\S)(?<=\S)/ ); + sub convert { + my $re = shift; + $re =~ s{ + \\ ( \\ | Y . ) + } + { $rules{$1} or invalid($re,$1) }sgex; + return $re; + } + +Now C<use customre> enables the new escape in constant regular +expressions, i.e., those without any runtime variable interpolations. +As documented in L<overload>, this conversion will work only over +literal parts of regular expressions. For C<\Y|$re\Y|> the variable +part of this regular expression needs to be converted explicitly +(but only if the special meaning of C<\Y|> should be enabled inside $re): + + use customre; + $re = <>; + chomp $re; + $re = customre::convert $re; + /\Y|$re\Y|/; + +=head2 SEE ALSO + +L<perlop/"Regexp Quote-Like Operators">. + +L<perlop/"Gory details of parsing quoted constructs">. + +L<perlfunc/pos>. + +L<perllocale>. + +I<Mastering Regular Expressions> (see L<perlbook>) by Jeffrey Friedl. |